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//这是你自己用来接受查询出来的数据的集合。 List > listMap1 = new LinkedList >();//这是我集合中的数据(泥萌可以拿去当静态数据用)[{"count":205,"ip":"10.0.30.96"},{"count":79,"ip":"10.0.30.76"},{"count":39,"ip":"10.0.30.75"},{"count":38,"ip":"10.0.30.83"},{"count":37,"ip":"10.0.30.78"},{"count":33,"ip":"10.0.30.84"},{"count":20,"ip":"10.0.30.53"},{"count":17,"ip":"10.0.10.112"},{"count":12,"ip":"10.0.30.79"},{"count":11,"ip":"10.0.30.81"},{"count":6057,"ip":"192.168.1.195"},{"count":2077,"ip":"192.168.1.97"},{"count":943,"ip":"192.168.1.70"},{"count":813,"ip":"192.168.1.100"},{"count":727,"ip":"192.168.1.79"},{"count":647,"ip":"192.168.1.87"},{"count":629,"ip":"192.168.1.21"},{"count":182,"ip":"192.168.1.155"},{"count":168,"ip":"192.168.1.95"},{"count":160,"ip":"192.168.1.93"}] // 数据的话 可以自己去手动添加静态的ang~//接下来到关键时刻了~ 要注意line.3位置的count 是对应你自己数据集合中的countCollections.sort(listMap1, new Comparator >(){ public int compare(Map o1,Map o2){ return (Long)o1.get("count")<(Long)o2.get("count")?1:( (Long)o1.get("count")==(Long)o2.get("count")?0:-1); } }); System.out.println("排序:"+listMap1);//然后就是叼叼哒的排序 long 是指你自己的count的类型，排序的话只是更改一下大于小于符号即可~ return (Long)o1.get("count")>(Long)o2.get("count")?1:( (Long)o1.get("count")==(Long)o2.get("count")?0:-1);//这是从小到大 return (Long)o1.get("count")<(Long)o2.get("count")?1:( (Long)o1.get("count")==(Long)o2.get("count")?0:-1);//这是从大到小//然后...... 就没有然后了
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转载于:https://www.cnblogs.com/assistants/p/10649895.html